Someone asked: Has anyone EVER figured out the math to that damn water-in-a-bottle-diffuse-the-bomb riddle? I actually have, in case anyone's wondering about it. If I remember right, they've got a 5, a 3, and they need 4. Fill the five, tip it into the 3, leaving 2. Empty out the three, and put the 2 in it. Then fill the five, and use that jug to fill up the remainder of the 3, which will leave 4 in the 5 gallon jug. Another possible way to do this: You fill up the 3 and tip these three gallons into the 5. Then you fill up the 3 and use this to fill up the 5. This leaves you with one in the 3 and five in the 5. Then you empty the 5 and tip the one from the 3 over, then fill up the 3. Then you've got three in the 3 and one in the 5. After you've tipped over the three this will leave you with four in the 5.